![SOLVED: For Sin a = 2/3 and Cos b = -1/4 with both in [pi/2.pi) Find Cos ( a-b) [2 Sart(15) - Sqrt(5) ] / 12 [2 Sqrt (5) Sqrt (3) ]/ 12](https://cdn.numerade.com/ask_images/4150e8e2965a46589e6825184fa18722.jpg "SOLVED: For Sin a = 2/3 and Cos b = -1/4 with both in [pi/2.pi) Find Cos ( a-b) [2 Sart(15) - Sqrt(5) ] / 12 [2 Sqrt (5) Sqrt (3) ]/ 12")
SOLVED: For Sin a = 2/3 and Cos b = -1/4 with both in [pi/2.pi) Find Cos ( a-b) [2 Sart(15) - Sqrt(5) ] / 12 [2 Sqrt (5) Sqrt (3) ]/ 12
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SOLVED: Evaluate the following method calls: a.Math.sqrt(4 j.Math.floor-2.5 b.Math.sin2 *Math.PI) k.Math.round(-2.5f) c.Math.cos2 *Math.PI) I.Math.round-2.5 d.Math.pow2,2 m.Math.rint(2.5 e.Math.log(Math.E) n.Math.ceil2.5 f.Math.exp1 o.Math.floor2.5 p ...
Ifint(-pi/4)^((3pi)/4)(e^(pi/4)dx)/((e^x+e^(pi/4))(sinx+cosx))=kint(-pi/2)^( pi/2)secx dx , then the value of k is (a) 1/2 (b) 1/(sqrt(2)) (c) 1/(2sqrt(2)) (d) -1/(sqrt(2))
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![Evaluate the integral int 2^3 [√(2x - )√(5 ( 4x - 5 ))+√(2x + )√(5 ( 4x - 5 )) ] dx](https://dwes9vv9u0550.cloudfront.net/images/12048498/4d707fbe-90ed-41ce-9139-c8b46daf2ff5.jpg "Evaluate the integral int 2^3 [√(2x - )√(5 ( 4x - 5 ))+√(2x + )√(5 ( 4x - 5 )) ] dx")
Evaluate the integral int 2^3 [√(2x - )√(5 ( 4x - 5 ))+√(2x + )√(5 ( 4x - 5 )) ] dx
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