If sum of all the solutions of the equation 8cosx.(cos(π/6+x).cos(π/6-x)-1/2)=1 in [0,π] is kπ, then k is equal to: - Sarthaks eConnect | Largest Online Education Community
![Let P(k)=(1+cos(pi/(4k))) (1+cos(((2k-1)pi)/(4k))) (1+cos(((2k+1)pi )/(4k)))(1+cos(((4k-1)pi)/(4k)))dot Then (a)P(3)=1/(16) (b) P(4)=(2-sqrt(2))/(16) P(5)=(3-sqrt(5))/(32) (d) P(6)(2-sqrt(3))/(16) Let P(k)=(1+cos(pi/(4k))) (1+cos(((2k-1)pi)/(4k))) (1+cos(((2k+1)pi )/(4k)))(1+cos(((4k-1)pi)/(4k)))dot Then (a)P(3)=1/(16) (b) P(4)=(2-sqrt(2))/(16) P(5)=(3-sqrt(5))/(32) (d) P(6)(2-sqrt(3))/(16)](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/22723_web.png)
Let P(k)=(1+cos(pi/(4k))) (1+cos(((2k-1)pi)/(4k))) (1+cos(((2k+1)pi )/(4k)))(1+cos(((4k-1)pi)/(4k)))dot Then (a)P(3)=1/(16) (b) P(4)=(2-sqrt(2))/(16) P(5)=(3-sqrt(5))/(32) (d) P(6)(2-sqrt(3))/(16)
![SOLVED:Use one of the identities cos(t+2 πk)=cost or sin(t+2 πk)=sint to evaluate each expression. (a) cos((π)/(4)+2 π) (b) sin((π)/(3)+2 π) (c) sin((π)/(2)-6 π) SOLVED:Use one of the identities cos(t+2 πk)=cost or sin(t+2 πk)=sint to evaluate each expression. (a) cos((π)/(4)+2 π) (b) sin((π)/(3)+2 π) (c) sin((π)/(2)-6 π)](https://cdn.numerade.com/previews/97da0263-ae1d-41ab-a2d2-bf70a40d7d8a.gif)
SOLVED:Use one of the identities cos(t+2 πk)=cost or sin(t+2 πk)=sint to evaluate each expression. (a) cos((π)/(4)+2 π) (b) sin((π)/(3)+2 π) (c) sin((π)/(2)-6 π)
Find the values of k so that the function f is continuous at the indicated point: f(x) = kx^2, if x pi at x = pi
![Find the value of the following :- `{:((a)sin((pi)/(6)),(b)cos ((pi)/(4))), ((c)tan((pi)/(3)), - YouTube Find the value of the following :- `{:((a)sin((pi)/(6)),(b)cos ((pi)/(4))), ((c)tan((pi)/(3)), - YouTube](https://i.ytimg.com/vi/vAY8P1rGi_o/maxresdefault.jpg?sqp=-oaymwEmCIAKENAF8quKqQMa8AEB-AH-CYAC0AWKAgwIABABGGIgYihiMA8=&rs=AOn4CLBNTpY19z8l8NPrxC4ThUFKKh5mbw)
Find the value of the following :- `{:((a)sin((pi)/(6)),(b)cos ((pi)/(4))), ((c)tan((pi)/(3)), - YouTube
![Sketch the graph of r(t) = \cos(\pi t)i + \sin(\pi t)j + t^2k, \ \ -1 \leq t \leq 1. | Homework.Study.com Sketch the graph of r(t) = \cos(\pi t)i + \sin(\pi t)j + t^2k, \ \ -1 \leq t \leq 1. | Homework.Study.com](https://homework.study.com/cimages/multimages/16/graph7958127347085344480.jpg)
Sketch the graph of r(t) = \cos(\pi t)i + \sin(\pi t)j + t^2k, \ \ -1 \leq t \leq 1. | Homework.Study.com
![Let `z_k= cos ((2 k pi)/(10))+ I sin ((2 k pi )/(10)), k = 1,2, ….9` - Sarthaks eConnect | Largest Online Education Community Let `z_k= cos ((2 k pi)/(10))+ I sin ((2 k pi )/(10)), k = 1,2, ….9` - Sarthaks eConnect | Largest Online Education Community](https://learnqa.s3.ap-south-1.amazonaws.com/images/16131821588139797897025349.png)